What are the solutions to the equation x^2-4x+16=18 ?

The solutions to the equation x^2-4x+16=18 are x=2+sqrt(6),x=2-sqrt(6)

Find the zeros of x^2-4x+16=18

The zeros of x^2-4x+16=18 are x=2+sqrt(6),x=2-sqrt(6)

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x^{2} - 4 x + 16 = 18

x = 2 + 6, x = 2 - 6

Decimal Notation

x = 4.44948 \dots, x = - 0.44948 \dots

Solution steps

x^{2} - 4 x + 16 = 18

Move

18

to the left side

x^{2} - 4 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 2) = 26

x_{1, 2} = \frac{- ( - 4 ) \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 6}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 6}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 6}{2 \cdot 1} : 2 + 6

x = \frac{- ( - 4 ) - 2 6}{2 \cdot 1} : 2 - 6

The solutions to the quadratic equation are:

x = 2 + 6, x = 2 - 6

2 x^{2} - 17 x + 16 = 0

(- a)^{2} - 4 (1) (- 2 a) = 0

v, v^{2} = u^{2} + 2 a s

x, (x - 0)^{2} = 4 p (y - 10)

2 y^{2} - y - 7 = 0

What are the solutions to the equation x^2-4x+16=18 ?
The solutions to the equation x^2-4x+16=18 are x=2+sqrt(6),x=2-sqrt(6)
Find the zeros of x^2-4x+16=18
The zeros of x^2-4x+16=18 are x=2+sqrt(6),x=2-sqrt(6)