What is -pi/2 <4x+pi< pi/2 ?

The solution to -pi/2 <4x+pi< pi/2 is -(3pi)/8 <x<-pi/8

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-pi/2 <4x+pi< pi/2

- \frac{π}{2} < 4 x + π < \frac{π}{2}

- \frac{3 π}{8} < x < - \frac{π}{8}

Interval Notation

(- \frac{3 π}{8}, - \frac{π}{8})

Decimal Notation

- 1.17809 \dots < x < - 0.39269 \dots

Solution steps

- \frac{π}{2} < 4 x + π < \frac{π}{2}

a < u < b

then

a < u and u < b

- \frac{π}{2} < 4 x + π and 4 x + π < \frac{π}{2}

- \frac{π}{2} < 4 x + π : x > - \frac{3 π}{8}

4 x + π < \frac{π}{2} : x < - \frac{π}{8}

Combine the intervals

x > - \frac{3 π}{8} and x < - \frac{π}{8}

Merge Overlapping Intervals

- \frac{3 π}{8} < x < - \frac{π}{8}

4 x^{2} - 26 x + 30

a^{2} + 10 a + 16

2 x^{2} - 5 x = 9

5 ∣ x - 4 ∣ > 10

- (x - 4) < 18 + 3 (2 x + 2)

What is -pi/2 <4x+pi< pi/2 ?
The solution to -pi/2 <4x+pi< pi/2 is -(3pi)/8 <x<-pi/8