What are the solutions to the equation ((x+x+20)x)/2 =119 ?

The solutions to the equation ((x+x+20)x)/2 =119 are x=7,x=-17

Find the zeros of ((x+x+20)x)/2 =119

The zeros of ((x+x+20)x)/2 =119 are x=7,x=-17

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\frac{( x + x + 20 ) x}{2} = 119

x = 7, x = - 17

Solution steps

\frac{( x + x + 20 ) x}{2} = 119

Multiply both sides by

2

x (2 x + 20) = 238

Expand

x (2 x + 20) : 2 x^{2} + 20 x

2 x^{2} + 20 x = 238

Move

238

to the left side

2 x^{2} + 20 x - 238 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 2 ( - 238 )}{2 \cdot 2}

2 0^{2} - 4 \cdot 2 (- 238) = 48

x_{1, 2} = \frac{- 20 \pm 48}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 20 + 48}{2 \cdot 2}, x_{2} = \frac{- 20 - 48}{2 \cdot 2}

x = \frac{- 20 + 48}{2 \cdot 2} : 7

x = \frac{- 20 - 48}{2 \cdot 2} : - 17

The solutions to the quadratic equation are:

x = 7, x = - 17

5 x^{2} + 60 x = - 100

3 x^{2} + 13 x - 31 = - 1

7 x^{2} - 3 = 1

x^{2} - 2 x + 18 = 0

4 x (x + 39) + 9 = 0

What are the solutions to the equation ((x+x+20)x)/2 =119 ?
The solutions to the equation ((x+x+20)x)/2 =119 are x=7,x=-17
Find the zeros of ((x+x+20)x)/2 =119
The zeros of ((x+x+20)x)/2 =119 are x=7,x=-17