What are the solutions to the equation y^2-6y+12=0 ?

The solutions to the equation y^2-6y+12=0 are y=3+sqrt(3)i,y=3-sqrt(3)i

Find the zeros of y^2-6y+12=0

The zeros of y^2-6y+12=0 are y=3+sqrt(3)i,y=3-sqrt(3)i

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y^{2} - 6 y + 12 = 0

y = 3 + 3 i, y = 3 - 3 i

Solution steps

y^{2} - 6 y + 12 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 12 : 23 i

y_{1, 2} = \frac{- ( - 6 ) \pm 2 3 i}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 6 ) + 2 3 i}{2 \cdot 1}, y_{2} = \frac{- ( - 6 ) - 2 3 i}{2 \cdot 1}

y = \frac{- ( - 6 ) + 2 3 i}{2 \cdot 1} : 3 + 3 i

y = \frac{- ( - 6 ) - 2 3 i}{2 \cdot 1} : 3 - 3 i

The solutions to the quadratic equation are:

y = 3 + 3 i, y = 3 - 3 i

4 y^{2} - (4 - y^{2}) = 4

x^{2} - 0.011 x - 0.063 = 0

3 x^{2} + 9 x = - 6

c^{2} + 12 c + 36 = 121

r^{2} - 16 r + 35 = 7

What are the solutions to the equation y^2-6y+12=0 ?
The solutions to the equation y^2-6y+12=0 are y=3+sqrt(3)i,y=3-sqrt(3)i
Find the zeros of y^2-6y+12=0
The zeros of y^2-6y+12=0 are y=3+sqrt(3)i,y=3-sqrt(3)i