What are the solutions to the equation 22-22x=(5x+3)(x-1) ?

The solutions to the equation 22-22x=(5x+3)(x-1) are x=1,x=-5

Find the zeros of 22-22x=(5x+3)(x-1)

The zeros of 22-22x=(5x+3)(x-1) are x=1,x=-5

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22 - 22 x = (5 x + 3) (x - 1)

x = 1, x = - 5

Solution steps

22 - 22 x = (5 x + 3) (x - 1)

Expand

(5 x + 3) (x - 1) : 5 x^{2} - 2 x - 3

22 - 22 x = 5 x^{2} - 2 x - 3

Switch sides

5 x^{2} - 2 x - 3 = 22 - 22 x

Move

22 x

to the left side

5 x^{2} + 20 x - 3 = 22

Move

22

to the left side

5 x^{2} + 20 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 5 ( - 25 )}{2 \cdot 5}

2 0^{2} - 4 \cdot 5 (- 25) = 30

x_{1, 2} = \frac{- 20 \pm 30}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 20 + 30}{2 \cdot 5}, x_{2} = \frac{- 20 - 30}{2 \cdot 5}

x = \frac{- 20 + 30}{2 \cdot 5} : 1

x = \frac{- 20 - 30}{2 \cdot 5} : - 5

The solutions to the quadratic equation are:

x = 1, x = - 5

- 4 n^{2} = 6 n + 16 - 5 n^{2}

w^{2} - w - 12 = 0

1050 = 5 \cdot t^{2}

21 x^{2} - 12 x - 9 = 0

(6 x + 10)^{2} = 125

What are the solutions to the equation 22-22x=(5x+3)(x-1) ?
The solutions to the equation 22-22x=(5x+3)(x-1) are x=1,x=-5
Find the zeros of 22-22x=(5x+3)(x-1)
The zeros of 22-22x=(5x+3)(x-1) are x=1,x=-5