What are the solutions to the equation 4t^2+12t-17=0 ?

The solutions to the equation 4t^2+12t-17=0 are t=(-3+sqrt(26))/2 ,t=-(3+sqrt(26))/2

Find the zeros of 4t^2+12t-17=0

The zeros of 4t^2+12t-17=0 are t=(-3+sqrt(26))/2 ,t=-(3+sqrt(26))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 t^{2} + 12 t - 17 = 0

t = \frac{- 3 + 26}{2}, t = - \frac{3 + 26}{2}

Decimal

t = 1.04950 \dots, t = - 4.04950 \dots

Solution steps

4 t^{2} + 12 t - 17 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 ( - 17 )}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 (- 17) = 426

t_{1, 2} = \frac{- 12 \pm 4 26}{2 \cdot 4}

Separate the solutions

t_{1} = \frac{- 12 + 4 26}{2 \cdot 4}, t_{2} = \frac{- 12 - 4 26}{2 \cdot 4}

t = \frac{- 12 + 4 26}{2 \cdot 4} : \frac{- 3 + 26}{2}

t = \frac{- 12 - 4 26}{2 \cdot 4} : - \frac{3 + 26}{2}

The solutions to the quadratic equation are:

t = \frac{- 3 + 26}{2}, t = - \frac{3 + 26}{2}

x^{2} - 9 = 0

2 s^{2} - 50 = 0

5 x^{2} - 6 x = 8

c = 1600 - 10 x + 0.25 x^{2}

- 2 x^{2} - x + 12

What are the solutions to the equation 4t^2+12t-17=0 ?
The solutions to the equation 4t^2+12t-17=0 are t=(-3+sqrt(26))/2 ,t=-(3+sqrt(26))/2
Find the zeros of 4t^2+12t-17=0
The zeros of 4t^2+12t-17=0 are t=(-3+sqrt(26))/2 ,t=-(3+sqrt(26))/2