What are the solutions to the equation quadraticformula x^2-1=0 ?

The solutions to the equation quadraticformula x^2-1=0 are x=1,x=-1

Find the zeros of quadraticformula x^2-1=0

The zeros of quadraticformula x^2-1=0 are x=1,x=-1

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x^{2} - 1 = 0

x = 1, x = - 1

Solution steps

x^{2} - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

0^{2} - 4 \cdot 1 \cdot (- 1) = 2

x_{1, 2} = \frac{- 0 \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 0 + 2}{2 \cdot 1}, x_{2} = \frac{- 0 - 2}{2 \cdot 1}

x = \frac{- 0 + 2}{2 \cdot 1} : 1

x = \frac{- 0 - 2}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 1, x = - 1

x, f = x^{2} - h^{2}

3 x^{2} = 13 x - 10

4 - 3 x - x^{2}

3 m^{2} - 9 m = 30

3 x^{2} - 5 x = 3 x + 5

What are the solutions to the equation quadraticformula x^2-1=0 ?
The solutions to the equation quadraticformula x^2-1=0 are x=1,x=-1
Find the zeros of quadraticformula x^2-1=0
The zeros of quadraticformula x^2-1=0 are x=1,x=-1