What are the solutions to the equation -4x^2-16x-12=0 ?

The solutions to the equation -4x^2-16x-12=0 are x=-3,x=-1

Find the zeros of -4x^2-16x-12=0

The zeros of -4x^2-16x-12=0 are x=-3,x=-1

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- 4 x^{2} - 16 x - 12 = 0

x = - 3, x = - 1

Solution steps

- 4 x^{2} - 16 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 ( - 4 ) ( - 12 )}{2 ( - 4 )}

(- 16)^{2} - 4 (- 4) (- 12) = 8

x_{1, 2} = \frac{- ( - 16 ) \pm 8}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 8}{2 ( - 4 )}, x_{2} = \frac{- ( - 16 ) - 8}{2 ( - 4 )}

x = \frac{- ( - 16 ) + 8}{2 ( - 4 )} : - 3

x = \frac{- ( - 16 ) - 8}{2 ( - 4 )} : - 1

The solutions to the quadratic equation are:

x = - 3, x = - 1

x^{2} + 6 x - 40 = 0

x + 7 = 4 (x^{2} + 7)

9 x^{2} = 12 x - 7

3 y^{2} - y + 2 = 0

x^{2} = 10 x - 24

What are the solutions to the equation -4x^2-16x-12=0 ?
The solutions to the equation -4x^2-16x-12=0 are x=-3,x=-1
Find the zeros of -4x^2-16x-12=0
The zeros of -4x^2-16x-12=0 are x=-3,x=-1