What are the solutions to the equation 3+5x=-9x^2 ?

The solutions to the equation 3+5x=-9x^2 are x=-5/18-i(sqrt(83))/(18),x=-5/18+i(sqrt(83))/(18)

Find the zeros of 3+5x=-9x^2

The zeros of 3+5x=-9x^2 are x=-5/18-i(sqrt(83))/(18),x=-5/18+i(sqrt(83))/(18)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 + 5 x = - 9 x^{2}

x = - \frac{5}{18} - i \frac{83}{18}, x = - \frac{5}{18} + i \frac{83}{18}

Solution steps

3 + 5 x = - 9 x^{2}

Switch sides

- 9 x^{2} = 3 + 5 x

Move

5 x

to the left side

- 9 x^{2} - 5 x = 3

Move

3

to the left side

- 9 x^{2} - 5 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 9 ) ( - 3 )}{2 ( - 9 )}

Simplify

(- 5)^{2} - 4 (- 9) (- 3) : 83 i

x_{1, 2} = \frac{- ( - 5 ) \pm 83 i}{2 ( - 9 )}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 83 i}{2 ( - 9 )}, x_{2} = \frac{- ( - 5 ) - 83 i}{2 ( - 9 )}

x = \frac{- ( - 5 ) + 83 i}{2 ( - 9 )} : - \frac{5}{18} - i \frac{83}{18}

x = \frac{- ( - 5 ) - 83 i}{2 ( - 9 )} : - \frac{5}{18} + i \frac{83}{18}

The solutions to the quadratic equation are:

x = - \frac{5}{18} - i \frac{83}{18}, x = - \frac{5}{18} + i \frac{83}{18}

4 x^{2} + 8 x + 1 = 2 x^{2}

x^{2} - 2 x + 5 = 85

- 3 x^{2} - 24 x - 46

65 x^{2} - 1 = x^{2}

x^{2} + 10 x + 9 = 0

What are the solutions to the equation 3+5x=-9x^2 ?
The solutions to the equation 3+5x=-9x^2 are x=-5/18-i(sqrt(83))/(18),x=-5/18+i(sqrt(83))/(18)
Find the zeros of 3+5x=-9x^2
The zeros of 3+5x=-9x^2 are x=-5/18-i(sqrt(83))/(18),x=-5/18+i(sqrt(83))/(18)