What are the solutions to the equation (2s-1)^2-255=0 ?

The solutions to the equation (2s-1)^2-255=0 are s=(sqrt(255)+1)/2 ,s=(-sqrt(255)+1)/2

Find the zeros of (2s-1)^2-255=0

The zeros of (2s-1)^2-255=0 are s=(sqrt(255)+1)/2 ,s=(-sqrt(255)+1)/2

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(2 s - 1)^{2} - 255 = 0

s = \frac{255 + 1}{2}, s = \frac{- 255 + 1}{2}

Decimal Notation

s = 8.48435 \dots, s = - 7.48435 \dots

Solution steps

(2 s - 1)^{2} - 255 = 0

Move

255

to the right side

(2 s - 1)^{2} = 255

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 s - 1 = 255 : s = \frac{255 + 1}{2}

Solve

2 s - 1 = - 255 : s = \frac{- 255 + 1}{2}

The solutions to the quadratic equation are:

s = \frac{255 + 1}{2}, s = \frac{- 255 + 1}{2}

13 x^{2} - x = 0

(r - 4) (r + 8) = - 24

l^{2} - 5 l - 36 = 0

12 x^{2} + 163 x + 15 = 0

1.002 x^{2} - 11.01 x + 0.01265 = 0

What are the solutions to the equation (2s-1)^2-255=0 ?
The solutions to the equation (2s-1)^2-255=0 are s=(sqrt(255)+1)/2 ,s=(-sqrt(255)+1)/2
Find the zeros of (2s-1)^2-255=0
The zeros of (2s-1)^2-255=0 are s=(sqrt(255)+1)/2 ,s=(-sqrt(255)+1)/2