What are the solutions to the equation 2k^2+6k=36 ?

The solutions to the equation 2k^2+6k=36 are k=3,k=-6

Find the zeros of 2k^2+6k=36

The zeros of 2k^2+6k=36 are k=3,k=-6

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2 k^{2} + 6 k = 36

k = 3, k = - 6

Solution steps

2 k^{2} + 6 k = 36

Move

36

to the left side

2 k^{2} + 6 k - 36 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 2 ( - 36 )}{2 \cdot 2}

6^{2} - 4 \cdot 2 (- 36) = 18

k_{1, 2} = \frac{- 6 \pm 18}{2 \cdot 2}

Separate the solutions

k_{1} = \frac{- 6 + 18}{2 \cdot 2}, k_{2} = \frac{- 6 - 18}{2 \cdot 2}

k = \frac{- 6 + 18}{2 \cdot 2} : 3

k = \frac{- 6 - 18}{2 \cdot 2} : - 6

The solutions to the quadratic equation are:

k = 3, k = - 6

2 r^{2} - 12 r + 18 = 0

x + 2 = 2 x^{2} - 4

n x^{2} = m

x^{2} + 7 x + 1

- 2.7 t^{2} + 40 t + 6.5 = 0

What are the solutions to the equation 2k^2+6k=36 ?
The solutions to the equation 2k^2+6k=36 are k=3,k=-6
Find the zeros of 2k^2+6k=36
The zeros of 2k^2+6k=36 are k=3,k=-6