What are the solutions to the equation 5x^2-5x+6=0 ?

The solutions to the equation 5x^2-5x+6=0 are x= 1/2+i(sqrt(95))/(10),x= 1/2-i(sqrt(95))/(10)

Find the zeros of 5x^2-5x+6=0

The zeros of 5x^2-5x+6=0 are x= 1/2+i(sqrt(95))/(10),x= 1/2-i(sqrt(95))/(10)

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5 x^{2} - 5 x + 6 = 0

x = \frac{1}{2} + i \frac{95}{10}, x = \frac{1}{2} - i \frac{95}{10}

Solution steps

5 x^{2} - 5 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 5 \cdot 6}{2 \cdot 5}

Simplify

(- 5)^{2} - 4 \cdot 5 \cdot 6 : 95 i

x_{1, 2} = \frac{- ( - 5 ) \pm 95 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 95 i}{2 \cdot 5}, x_{2} = \frac{- ( - 5 ) - 95 i}{2 \cdot 5}

x = \frac{- ( - 5 ) + 95 i}{2 \cdot 5} : \frac{1}{2} + i \frac{95}{10}

x = \frac{- ( - 5 ) - 95 i}{2 \cdot 5} : \frac{1}{2} - i \frac{95}{10}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{95}{10}, x = \frac{1}{2} - i \frac{95}{10}

144 = 5 x^{2} - 8 x + 11

(18 - R)^{2} + (9 - R)^{2} = R^{2}

3 x^{2} - 10 + 3 = 0

2 n^{2} - 5 n - 12 = 0

0 = x^{2} - 26 x + 48

What are the solutions to the equation 5x^2-5x+6=0 ?
The solutions to the equation 5x^2-5x+6=0 are x= 1/2+i(sqrt(95))/(10),x= 1/2-i(sqrt(95))/(10)
Find the zeros of 5x^2-5x+6=0
The zeros of 5x^2-5x+6=0 are x= 1/2+i(sqrt(95))/(10),x= 1/2-i(sqrt(95))/(10)