What are the solutions to the equation a^2+3a-1=0 ?

The solutions to the equation a^2+3a-1=0 are a=(-3+sqrt(13))/2 ,a=(-3-sqrt(13))/2

Find the zeros of a^2+3a-1=0

The zeros of a^2+3a-1=0 are a=(-3+sqrt(13))/2 ,a=(-3-sqrt(13))/2

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a^{2} + 3 a - 1 = 0

a = \frac{- 3 + 13}{2}, a = \frac{- 3 - 13}{2}

Decimal Notation

a = 0.30277 \dots, a = - 3.30277 \dots

Solution steps

a^{2} + 3 a - 1 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 1) = 13

a_{1, 2} = \frac{- 3 \pm 13}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 3 + 13}{2 \cdot 1}, a_{2} = \frac{- 3 - 13}{2 \cdot 1}

a = \frac{- 3 + 13}{2 \cdot 1} : \frac{- 3 + 13}{2}

a = \frac{- 3 - 13}{2 \cdot 1} : \frac{- 3 - 13}{2}

The solutions to the quadratic equation are:

a = \frac{- 3 + 13}{2}, a = \frac{- 3 - 13}{2}

3 w^{2} - 4 w - 55 = 0

2 x^{2} - 7 = - 39

27 c^{2} - 54 c + 18 = 0

5 x^{2} - 5 x - 4 = 0

5 x^{2} - 18 = 0

What are the solutions to the equation a^2+3a-1=0 ?
The solutions to the equation a^2+3a-1=0 are a=(-3+sqrt(13))/2 ,a=(-3-sqrt(13))/2
Find the zeros of a^2+3a-1=0
The zeros of a^2+3a-1=0 are a=(-3+sqrt(13))/2 ,a=(-3-sqrt(13))/2