What are the solutions to the equation -3x^2+24x=15 ?

The solutions to the equation -3x^2+24x=15 are x=4-sqrt(11),x=4+sqrt(11)

Find the zeros of -3x^2+24x=15

The zeros of -3x^2+24x=15 are x=4-sqrt(11),x=4+sqrt(11)

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- 3 x^{2} + 24 x = 15

x = 4 - 11, x = 4 + 11

Decimal Notation

x = 0.68337 \dots, x = 7.31662 \dots

Solution steps

- 3 x^{2} + 24 x = 15

Move

15

to the left side

- 3 x^{2} + 24 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 ( - 3 ) ( - 15 )}{2 ( - 3 )}

2 4^{2} - 4 (- 3) (- 15) = 611

x_{1, 2} = \frac{- 24 \pm 6 11}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 24 + 6 11}{2 ( - 3 )}, x_{2} = \frac{- 24 - 6 11}{2 ( - 3 )}

x = \frac{- 24 + 6 11}{2 ( - 3 )} : 4 - 11

x = \frac{- 24 - 6 11}{2 ( - 3 )} : 4 + 11

The solutions to the quadratic equation are:

x = 4 - 11, x = 4 + 11

\frac{5}{4} q^{2} = - \frac{5}{4}

100 r^{2} - 5 = 76

3 x^{2} = - 8 x

2 (x + 1)^{2} - 3 = (x - 2) (x + 2)

3 m^{2} + 5 m + 1 = 0

What are the solutions to the equation -3x^2+24x=15 ?
The solutions to the equation -3x^2+24x=15 are x=4-sqrt(11),x=4+sqrt(11)
Find the zeros of -3x^2+24x=15
The zeros of -3x^2+24x=15 are x=4-sqrt(11),x=4+sqrt(11)