What are the solutions to the equation 0=(12-x^2)/8 ?

The solutions to the equation 0=(12-x^2)/8 are x=2sqrt(3),x=-2sqrt(3)

Find the zeros of 0=(12-x^2)/8

The zeros of 0=(12-x^2)/8 are x=2sqrt(3),x=-2sqrt(3)

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0 = \frac{12 - x ^{2}}{8}

x = 23, x = - 23

Decimal Notation

x = 3.46410 \dots, x = - 3.46410 \dots

Solution steps

0 = \frac{12 - x ^{2}}{8}

Switch sides

\frac{12 - x ^{2}}{8} = 0

Multiply both sides by

8

12 - x^{2} = 0

Move

12

to the right side

- x^{2} = - 12

Divide both sides by

- 1

x^{2} = 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 12, x = - 12

12 = 23

- 12 = - 23

x = 23, x = - 23

- 6 x^{2} + 3 x = 0

6 x^{2} - 54 x + 36 = 0

b^{2} - 2 b - 15 = 0

x, s (x) = x^{2} - 6 x + 5

x, s (x) = x^{2} - 6 x + 8

What are the solutions to the equation 0=(12-x^2)/8 ?
The solutions to the equation 0=(12-x^2)/8 are x=2sqrt(3),x=-2sqrt(3)
Find the zeros of 0=(12-x^2)/8
The zeros of 0=(12-x^2)/8 are x=2sqrt(3),x=-2sqrt(3)