What are the solutions to the equation 1=x^2-4 ?

The solutions to the equation 1=x^2-4 are x=sqrt(5),x=-sqrt(5)

Find the zeros of 1=x^2-4

The zeros of 1=x^2-4 are x=sqrt(5),x=-sqrt(5)

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1 = x^{2} - 4

x = 5, x = - 5

Decimal Notation

x = 2.23606 \dots, x = - 2.23606 \dots

Solution steps

1 = x^{2} - 4

Switch sides

x^{2} - 4 = 1

Move

4

to the right side

x^{2} = 5

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 5, x = - 5

5 a^{2} - 12 a + 3 = 0

x^{2} + 6 x - 55 = 0

2 x^{2} - 7 = 11

x^{2} + 10 x + 1

x^{2} + 10 x + 5

What are the solutions to the equation 1=x^2-4 ?
The solutions to the equation 1=x^2-4 are x=sqrt(5),x=-sqrt(5)
Find the zeros of 1=x^2-4
The zeros of 1=x^2-4 are x=sqrt(5),x=-sqrt(5)