What are the solutions to the equation 3a^2-5a+7=5 ?

The solutions to the equation 3a^2-5a+7=5 are a=1,a= 2/3

Find the zeros of 3a^2-5a+7=5

The zeros of 3a^2-5a+7=5 are a=1,a= 2/3

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3 a^{2} - 5 a + 7 = 5

a = 1, a = \frac{2}{3}

Decimal Notation

a = 1, a = 0.66666 \dots

Solution steps

3 a^{2} - 5 a + 7 = 5

Move

5

to the left side

3 a^{2} - 5 a + 2 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 \cdot 2 = 1

a_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 3}

Separate the solutions

a_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 3}, a_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 3}

a = \frac{- ( - 5 ) + 1}{2 \cdot 3} : 1

a = \frac{- ( - 5 ) - 1}{2 \cdot 3} : \frac{2}{3}

The solutions to the quadratic equation are:

a = 1, a = \frac{2}{3}

8 x - 8 x \cdot (\frac{x}{2}) = 0

- 8 x^{2} - 7 x - 1 = 0

x - 4 x^{2} = 0

- 2.7 t^{2} + 40 t - 3.5 = 0

x (x + 4) = 2

What are the solutions to the equation 3a^2-5a+7=5 ?
The solutions to the equation 3a^2-5a+7=5 are a=1,a= 2/3
Find the zeros of 3a^2-5a+7=5
The zeros of 3a^2-5a+7=5 are a=1,a= 2/3