What are the solutions to the equation m^2+12m+20=0 ?

The solutions to the equation m^2+12m+20=0 are m=-2,m=-10

Find the zeros of m^2+12m+20=0

The zeros of m^2+12m+20=0 are m=-2,m=-10

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m^{2} + 12 m + 20 = 0

m = - 2, m = - 10

Solution steps

m^{2} + 12 m + 20 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 20 = 8

m_{1, 2} = \frac{- 12 \pm 8}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 12 + 8}{2 \cdot 1}, m_{2} = \frac{- 12 - 8}{2 \cdot 1}

m = \frac{- 12 + 8}{2 \cdot 1} : - 2

m = \frac{- 12 - 8}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

m = - 2, m = - 10

- 3 x^{2} - 120 = 0

4 x^{2} + 3 x - 22 = 0

E, P = \frac{E ^{2}}{R}

6 + 2 x = 5 x^{2}

(x - 3) \cdot (2 x - 5) = 0

What are the solutions to the equation m^2+12m+20=0 ?
The solutions to the equation m^2+12m+20=0 are m=-2,m=-10
Find the zeros of m^2+12m+20=0
The zeros of m^2+12m+20=0 are m=-2,m=-10