What are the solutions to the equation 5x^2-3x+3=3-2x^2 ?

The solutions to the equation 5x^2-3x+3=3-2x^2 are x= 3/7 ,x=0

Find the zeros of 5x^2-3x+3=3-2x^2

The zeros of 5x^2-3x+3=3-2x^2 are x= 3/7 ,x=0

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5 x^{2} - 3 x + 3 = 3 - 2 x^{2}

x = \frac{3}{7}, x = 0

Decimal Notation

x = 0.42857 \dots, x = 0

Solution steps

5 x^{2} - 3 x + 3 = 3 - 2 x^{2}

Move

2 x^{2}

to the left side

7 x^{2} - 3 x + 3 = 3

Move

3

to the left side

7 x^{2} - 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 7 \cdot 0}{2 \cdot 7}

(- 3)^{2} - 4 \cdot 7 \cdot 0 = 3

x_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 7}, x_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 7}

x = \frac{- ( - 3 ) + 3}{2 \cdot 7} : \frac{3}{7}

x = \frac{- ( - 3 ) - 3}{2 \cdot 7} : 0

The solutions to the quadratic equation are:

x = \frac{3}{7}, x = 0

x, f (x^{2} + 1) = 5 x + 3

\frac{x ^{2}}{2} + 2 x + 2 = 0

\frac{- 1}{500} (x - 100)^{2} + 20 = 0

5 x^{2} + x - \frac{1}{5} = 0

v^{2} = 32

What are the solutions to the equation 5x^2-3x+3=3-2x^2 ?
The solutions to the equation 5x^2-3x+3=3-2x^2 are x= 3/7 ,x=0
Find the zeros of 5x^2-3x+3=3-2x^2
The zeros of 5x^2-3x+3=3-2x^2 are x= 3/7 ,x=0