What are the solutions to the equation ((x-1)^2)/3 =7 ?

The solutions to the equation ((x-1)^2)/3 =7 are x=sqrt(21)+1,x=-sqrt(21)+1

Find the zeros of ((x-1)^2)/3 =7

The zeros of ((x-1)^2)/3 =7 are x=sqrt(21)+1,x=-sqrt(21)+1

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\frac{( x - 1 ) ^{2}}{3} = 7

x = 21 + 1, x = - 21 + 1

Decimal Notation

x = 5.58257 \dots, x = - 3.58257 \dots

Solution steps

\frac{( x - 1 ) ^{2}}{3} = 7

Multiply both sides by

3

(x - 1)^{2} = 21

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = 21 : x = 21 + 1

Solve

x - 1 = - 21 : x = - 21 + 1

The solutions to the quadratic equation are:

x = 21 + 1, x = - 21 + 1

x, x^{2} - 2 x = z^{2} - 2 z

- 4 x^{2} + 6 x + 1 = 0

28 + x = 100 - x^{2}

4 x^{2} - 9 - 2 (2 x - 3) + x (2 x - 3) = 0

(x - 6) (2 - x) = (x + 3)^{2} - (x - 2)^{2}

What are the solutions to the equation ((x-1)^2)/3 =7 ?
The solutions to the equation ((x-1)^2)/3 =7 are x=sqrt(21)+1,x=-sqrt(21)+1
Find the zeros of ((x-1)^2)/3 =7
The zeros of ((x-1)^2)/3 =7 are x=sqrt(21)+1,x=-sqrt(21)+1