What are the solutions to the equation -3x^2-18x-12=0 ?

The solutions to the equation -3x^2-18x-12=0 are x=-3-sqrt(5),x=-3+sqrt(5)

Find the zeros of -3x^2-18x-12=0

The zeros of -3x^2-18x-12=0 are x=-3-sqrt(5),x=-3+sqrt(5)

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- 3 x^{2} - 18 x - 12 = 0

x = - 3 - 5, x = - 3 + 5

Decimal Notation

x = - 5.23606 \dots, x = - 0.76393 \dots

Solution steps

- 3 x^{2} - 18 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 ( - 3 ) ( - 12 )}{2 ( - 3 )}

(- 18)^{2} - 4 (- 3) (- 12) = 65

x_{1, 2} = \frac{- ( - 18 ) \pm 6 5}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 6 5}{2 ( - 3 )}, x_{2} = \frac{- ( - 18 ) - 6 5}{2 ( - 3 )}

x = \frac{- ( - 18 ) + 6 5}{2 ( - 3 )} : - 3 - 5

x = \frac{- ( - 18 ) - 6 5}{2 ( - 3 )} : - 3 + 5

The solutions to the quadratic equation are:

x = - 3 - 5, x = - 3 + 5

\frac{1}{2} x^{2} = 1

\frac{1}{2} x^{2} = 2

0 = x^{2} - 2 x + 9

x^{2} = 4 x - 1

6 x^{2} - 7 x = 10

What are the solutions to the equation -3x^2-18x-12=0 ?
The solutions to the equation -3x^2-18x-12=0 are x=-3-sqrt(5),x=-3+sqrt(5)
Find the zeros of -3x^2-18x-12=0
The zeros of -3x^2-18x-12=0 are x=-3-sqrt(5),x=-3+sqrt(5)