What are the solutions to the equation u^2-10u+21=0 ?

The solutions to the equation u^2-10u+21=0 are u=7,u=3

Find the zeros of u^2-10u+21=0

The zeros of u^2-10u+21=0 are u=7,u=3

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u^{2} - 10 u + 21 = 0

u = 7, u = 3

Solution steps

u^{2} - 10 u + 21 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 21}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 21 = 4

u_{1, 2} = \frac{- ( - 10 ) \pm 4}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 10 ) + 4}{2 \cdot 1}, u_{2} = \frac{- ( - 10 ) - 4}{2 \cdot 1}

u = \frac{- ( - 10 ) + 4}{2 \cdot 1} : 7

u = \frac{- ( - 10 ) - 4}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

u = 7, u = 3

2 y^{2} - 4 y + 3 = 0

(x - 9)^{2} = - 3

x, f (x + 2) = 2 x^{2} + 3

y (y - 4) = - 8

y, 36 + y^{2} + z^{2} = 4

What are the solutions to the equation u^2-10u+21=0 ?
The solutions to the equation u^2-10u+21=0 are u=7,u=3
Find the zeros of u^2-10u+21=0
The zeros of u^2-10u+21=0 are u=7,u=3