What are the solutions to the equation solvefor x,f(x-2)=x^2 ?

The solutions to the equation solvefor x,f(x-2)=x^2 are x=(f+sqrt(f^2-8f))/2 ,x=(f-sqrt(f^2-8f))/2

Find the zeros of solvefor x,f(x-2)=x^2

The zeros of solvefor x,f(x-2)=x^2 are x=(f+sqrt(f^2-8f))/2 ,x=(f-sqrt(f^2-8f))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

x, f (x - 2) = x^{2}

x = \frac{f + f ^{2} - 8 f}{2}, x = \frac{f - f ^{2} - 8 f}{2}

Solution steps

f (x - 2) = x^{2}

Expand

f (x - 2) : x f - 2 f

x f - 2 f = x^{2}

Switch sides

x^{2} = x f - 2 f

Move

2 f

to the left side

x^{2} + 2 f = x f

Move

x f

to the left side

x^{2} + 2 f - x f = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - f x + 2 f = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - f ) \pm ( - f ) ^{2} - 4 \cdot 1 \cdot 2 f}{2 \cdot 1}

Simplify

(- f)^{2} - 4 \cdot 1 \cdot 2 f : f^{2} - 8 f

x_{1, 2} = \frac{- ( - f ) \pm f ^{2} - 8 f}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - f ) + f ^{2} - 8 f}{2 \cdot 1}, x_{2} = \frac{- ( - f ) - f ^{2} - 8 f}{2 \cdot 1}

x = \frac{- ( - f ) + f ^{2} - 8 f}{2 \cdot 1} : \frac{f + f ^{2} - 8 f}{2}

x = \frac{- ( - f ) - f ^{2} - 8 f}{2 \cdot 1} : \frac{f - f ^{2} - 8 f}{2}

The solutions to the quadratic equation are:

x = \frac{f + f ^{2} - 8 f}{2}, x = \frac{f - f ^{2} - 8 f}{2}

15 = x^{2}

(x + 1)^{2} - 8 = 0

x (21 - x) = 20

- 4 n^{2} = - 64

2 x^{2} + 12 x - 14

What are the solutions to the equation solvefor x,f(x-2)=x^2 ?
The solutions to the equation solvefor x,f(x-2)=x^2 are x=(f+sqrt(f^2-8f))/2 ,x=(f-sqrt(f^2-8f))/2
Find the zeros of solvefor x,f(x-2)=x^2
The zeros of solvefor x,f(x-2)=x^2 are x=(f+sqrt(f^2-8f))/2 ,x=(f-sqrt(f^2-8f))/2