What are the solutions to the equation -x^2-7x+5=0 ?

The solutions to the equation -x^2-7x+5=0 are x=-(7+sqrt(69))/2 ,x=(sqrt(69)-7)/2

Find the zeros of -x^2-7x+5=0

The zeros of -x^2-7x+5=0 are x=-(7+sqrt(69))/2 ,x=(sqrt(69)-7)/2

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- x^{2} - 7 x + 5 = 0

x = - \frac{7 + 69}{2}, x = \frac{69 - 7}{2}

Decimal Notation

x = - 7.65331 \dots, x = 0.65331 \dots

Solution steps

- x^{2} - 7 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 ( - 1 ) \cdot 5}{2 ( - 1 )}

(- 7)^{2} - 4 (- 1) \cdot 5 = 69

x_{1, 2} = \frac{- ( - 7 ) \pm 69}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 69}{2 ( - 1 )}, x_{2} = \frac{- ( - 7 ) - 69}{2 ( - 1 )}

x = \frac{- ( - 7 ) + 69}{2 ( - 1 )} : - \frac{7 + 69}{2}

x = \frac{- ( - 7 ) - 69}{2 ( - 1 )} : \frac{69 - 7}{2}

The solutions to the quadratic equation are:

x = - \frac{7 + 69}{2}, x = \frac{69 - 7}{2}

6 x^{2} + 7 = 3 x^{2} + 250

2 x^{2} - 8 x + 80 = 2 (x + 10)

x^{2} + 1 = 0, e x^{2} - 1 = 0

6 x^{2} + x = 2

1 5^{2} = 9^{2} + y^{2}

What are the solutions to the equation -x^2-7x+5=0 ?
The solutions to the equation -x^2-7x+5=0 are x=-(7+sqrt(69))/2 ,x=(sqrt(69)-7)/2
Find the zeros of -x^2-7x+5=0
The zeros of -x^2-7x+5=0 are x=-(7+sqrt(69))/2 ,x=(sqrt(69)-7)/2