What are the solutions to the equation 0=-x^2+3x-2 ?

The solutions to the equation 0=-x^2+3x-2 are x=1,x=2

Find the zeros of 0=-x^2+3x-2

The zeros of 0=-x^2+3x-2 are x=1,x=2

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0 = - x^{2} + 3 x - 2

x = 1, x = 2

Solution steps

0 = - x^{2} + 3 x - 2

Switch sides

- x^{2} + 3 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) ( - 2 )}{2 ( - 1 )}

3^{2} - 4 (- 1) (- 2) = 1

x_{1, 2} = \frac{- 3 \pm 1}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 3 + 1}{2 ( - 1 )}, x_{2} = \frac{- 3 - 1}{2 ( - 1 )}

x = \frac{- 3 + 1}{2 ( - 1 )} : 1

x = \frac{- 3 - 1}{2 ( - 1 )} : 2

The solutions to the quadratic equation are:

x = 1, x = 2

- 3 x^{2} + 12 x

x, f (x + h) = 10 + 3 x^{2}

x^{2} - 8 x - 38 = 0

- 5 x^{2} + 35 x - 60 = 0

(x + 3)^{2} - 10 = 2

What are the solutions to the equation 0=-x^2+3x-2 ?
The solutions to the equation 0=-x^2+3x-2 are x=1,x=2
Find the zeros of 0=-x^2+3x-2
The zeros of 0=-x^2+3x-2 are x=1,x=2