What are the solutions to the equation 4x^2-24x-16=0 ?

The solutions to the equation 4x^2-24x-16=0 are x=3+sqrt(13),x=3-sqrt(13)

Find the zeros of 4x^2-24x-16=0

The zeros of 4x^2-24x-16=0 are x=3+sqrt(13),x=3-sqrt(13)

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4 x^{2} - 24 x - 16 = 0

x = 3 + 13, x = 3 - 13

Decimal Notation

x = 6.60555 \dots, x = - 0.60555 \dots

Solution steps

4 x^{2} - 24 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 4 ( - 16 )}{2 \cdot 4}

(- 24)^{2} - 4 \cdot 4 (- 16) = 813

x_{1, 2} = \frac{- ( - 24 ) \pm 8 13}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 8 13}{2 \cdot 4}, x_{2} = \frac{- ( - 24 ) - 8 13}{2 \cdot 4}

x = \frac{- ( - 24 ) + 8 13}{2 \cdot 4} : 3 + 13

x = \frac{- ( - 24 ) - 8 13}{2 \cdot 4} : 3 - 13

The solutions to the quadratic equation are:

x = 3 + 13, x = 3 - 13

6 x^{2} - 45 = 0

- 5 (- x + 6) - x = xx

5 x^{2} + 10 = 30

4 (x + 8) (x - 5) = 0

2 4^{2} + x^{2} = 3 0^{2}

What are the solutions to the equation 4x^2-24x-16=0 ?
The solutions to the equation 4x^2-24x-16=0 are x=3+sqrt(13),x=3-sqrt(13)
Find the zeros of 4x^2-24x-16=0
The zeros of 4x^2-24x-16=0 are x=3+sqrt(13),x=3-sqrt(13)