What are the solutions to the equation x^2-2=3x^2+4x ?

The solutions to the equation x^2-2=3x^2+4x are x=-1

Find the zeros of x^2-2=3x^2+4x

The zeros of x^2-2=3x^2+4x are x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 2 = 3 x^{2} + 4 x

x = - 1

Solution steps

x^{2} - 2 = 3 x^{2} + 4 x

Move

4 x

to the left side

x^{2} - 2 - 4 x = 3 x^{2}

Move

3 x^{2}

to the left side

- 2 x^{2} - 4 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 2 ) ( - 2 )}{2 ( - 2 )}

(- 4)^{2} - 4 (- 2) (- 2) = 0

x_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 ( - 2 )}

x = \frac{- ( - 4 )}{2 ( - 2 )}

\frac{- ( - 4 )}{2 ( - 2 )} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

(x - 2)^{2} - 3 = - 3

(4 - 3 x)^{2} = x

9 x (x - 4) = 2 x (x - 4)

4 - x^{2} = 5 x

x, 2 x^{2} y = 7

What are the solutions to the equation x^2-2=3x^2+4x ?
The solutions to the equation x^2-2=3x^2+4x are x=-1
Find the zeros of x^2-2=3x^2+4x
The zeros of x^2-2=3x^2+4x are x=-1