What are the solutions to the equation x^2=25^2+7^2 ?

The solutions to the equation x^2=25^2+7^2 are x=sqrt(674),x=-sqrt(674)

Find the zeros of x^2=25^2+7^2

The zeros of x^2=25^2+7^2 are x=sqrt(674),x=-sqrt(674)

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x^{2} = 2 5^{2} + 7^{2}

x = 674, x = - 674

Decimal Notation

x = 25.96150 \dots, x = - 25.96150 \dots

Solution steps

x^{2} = 2 5^{2} + 7^{2}

Simplify

2 5^{2} + 7^{2} : 674

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 674, x = - 674

144 = x^{2} - 52

(50 - 2 x) (80 - 2 x) = 2000

- 2 x^{2} + 3 x = - 1

24 x^{2} - 50 x - 20 = 2 x

- 6 x^{2} + 17 = - 133

What are the solutions to the equation x^2=25^2+7^2 ?
The solutions to the equation x^2=25^2+7^2 are x=sqrt(674),x=-sqrt(674)
Find the zeros of x^2=25^2+7^2
The zeros of x^2=25^2+7^2 are x=sqrt(674),x=-sqrt(674)