What are the solutions to the equation 0=(x-1)^2+3 ?

The solutions to the equation 0=(x-1)^2+3 are x=sqrt(3)i+1,x=-sqrt(3)i+1

Find the zeros of 0=(x-1)^2+3

The zeros of 0=(x-1)^2+3 are x=sqrt(3)i+1,x=-sqrt(3)i+1

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0 = (x - 1)^{2} + 3

x = 3 i + 1, x = - 3 i + 1

Solution steps

0 = (x - 1)^{2} + 3

Switch sides

(x - 1)^{2} + 3 = 0

Move

3

to the right side

(x - 1)^{2} = - 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = - 3 : x = 3 i + 1

Solve

x - 1 = - - 3 : x = - 3 i + 1

The solutions to the quadratic equation are:

x = 3 i + 1, x = - 3 i + 1

- \frac{3}{4} + 2

10 + 6 x \leq 52

x + 1 - 2 x - 1 < 0

6 x + 8 y + 40

x^{\frac{1}{3}} \cdot x^{\frac{1}{5}}

What are the solutions to the equation 0=(x-1)^2+3 ?
The solutions to the equation 0=(x-1)^2+3 are x=sqrt(3)i+1,x=-sqrt(3)i+1
Find the zeros of 0=(x-1)^2+3
The zeros of 0=(x-1)^2+3 are x=sqrt(3)i+1,x=-sqrt(3)i+1