What are the solutions to the equation -2x^2+11x-12=0 ?

The solutions to the equation -2x^2+11x-12=0 are x= 3/2 ,x=4

Find the zeros of -2x^2+11x-12=0

The zeros of -2x^2+11x-12=0 are x= 3/2 ,x=4

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- 2 x^{2} + 11 x - 12 = 0

x = \frac{3}{2}, x = 4

Decimal Notation

x = 1.5, x = 4

Solution steps

- 2 x^{2} + 11 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 ( - 2 ) ( - 12 )}{2 ( - 2 )}

1 1^{2} - 4 (- 2) (- 12) = 5

x_{1, 2} = \frac{- 11 \pm 5}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 11 + 5}{2 ( - 2 )}, x_{2} = \frac{- 11 - 5}{2 ( - 2 )}

x = \frac{- 11 + 5}{2 ( - 2 )} : \frac{3}{2}

x = \frac{- 11 - 5}{2 ( - 2 )} : 4

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = 4

v w^{2} + y = x, w

14 x^{2} + 33 x = 3 x^{2} + 3 x + 1

(x + 2)^{2} - 3 = \frac{2 x - 5}{3}

7.9461 x^{2} + 7.2 x - 7.9461 = 0

x, f = x^{2} + 4 k x + (3 + 11 k)

What are the solutions to the equation -2x^2+11x-12=0 ?
The solutions to the equation -2x^2+11x-12=0 are x= 3/2 ,x=4
Find the zeros of -2x^2+11x-12=0
The zeros of -2x^2+11x-12=0 are x= 3/2 ,x=4