What are the solutions to the equation 36y^2-81=0 ?

The solutions to the equation 36y^2-81=0 are y= 3/2 ,y=-3/2

Find the zeros of 36y^2-81=0

The zeros of 36y^2-81=0 are y= 3/2 ,y=-3/2

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36 y^{2} - 81 = 0

y = \frac{3}{2}, y = - \frac{3}{2}

Decimal Notation

y = 1.5, y = - 1.5

Solution steps

36 y^{2} - 81 = 0

Move

81

to the right side

36 y^{2} = 81

Divide both sides by

36

y^{2} = \frac{9}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{9}{4}, y = - \frac{9}{4}

\frac{9}{4} = \frac{3}{2}

- \frac{9}{4} = - \frac{3}{2}

y = \frac{3}{2}, y = - \frac{3}{2}

2 x (x - 2) = 4 x^{2} - 5 x

xx + 3 x + 2 = 0

12 a^{2} - 4 a - 13 = 5 a + 8

x, (2 x + 3) (x + 4) = 1

2 u^{2} - 7 u + 3 = 0

What are the solutions to the equation 36y^2-81=0 ?
The solutions to the equation 36y^2-81=0 are y= 3/2 ,y=-3/2
Find the zeros of 36y^2-81=0
The zeros of 36y^2-81=0 are y= 3/2 ,y=-3/2