What are the solutions to the equation 2m^2-10=36 ?

The solutions to the equation 2m^2-10=36 are m=sqrt(23),m=-sqrt(23)

Find the zeros of 2m^2-10=36

The zeros of 2m^2-10=36 are m=sqrt(23),m=-sqrt(23)

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2 m^{2} - 10 = 36

m = 23, m = - 23

Decimal Notation

m = 4.79583 \dots, m = - 4.79583 \dots

Solution steps

2 m^{2} - 10 = 36

Move

10

to the right side

2 m^{2} = 46

Divide both sides by

2

m^{2} = 23

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

m = 23, m = - 23

5 (14 + 5) = s^{2} - 7^{2}

t, d = \frac{g t ^{2}}{2}

2 x^{2} = 5 x + 6

1.24 a^{2} + 47.5 a - 1917.81 = 0

(5 a - 1)^{2} = 1

What are the solutions to the equation 2m^2-10=36 ?
The solutions to the equation 2m^2-10=36 are m=sqrt(23),m=-sqrt(23)
Find the zeros of 2m^2-10=36
The zeros of 2m^2-10=36 are m=sqrt(23),m=-sqrt(23)