What are the solutions to the equation 2(x-3)^2-6=-4 ?

The solutions to the equation 2(x-3)^2-6=-4 are x=4,x=2

Find the zeros of 2(x-3)^2-6=-4

The zeros of 2(x-3)^2-6=-4 are x=4,x=2

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2 (x - 3)^{2} - 6 = - 4

x = 4, x = 2

Solution steps

2 (x - 3)^{2} - 6 = - 4

Move

6

to the right side

2 (x - 3)^{2} = 2

Divide both sides by

2

(x - 3)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = 1 : x = 4

Solve

x - 3 = - 1 : x = 2

The solutions to the quadratic equation are:

x = 4, x = 2

3 x^{2} + 3 x + 15 = 0

0 = x (x + 5)

x^{2} - 4 x = 32

9^{2} + b^{2} = 1 2^{2}

6 y^{2} + 9 y = 0

What are the solutions to the equation 2(x-3)^2-6=-4 ?
The solutions to the equation 2(x-3)^2-6=-4 are x=4,x=2
Find the zeros of 2(x-3)^2-6=-4
The zeros of 2(x-3)^2-6=-4 are x=4,x=2