What are the solutions to the equation 3(w+5)^2=27 ?

The solutions to the equation 3(w+5)^2=27 are w=-2,w=-8

Find the zeros of 3(w+5)^2=27

The zeros of 3(w+5)^2=27 are w=-2,w=-8

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3 (w + 5)^{2} = 27

w = - 2, w = - 8

Solution steps

3 (w + 5)^{2} = 27

Divide both sides by

3

(w + 5)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

w + 5 = 9 : w = - 2

Solve

w + 5 = - 9 : w = - 8

The solutions to the quadratic equation are:

w = - 2, w = - 8

2 d (d - 6) = 0

x (x + 7) - 3 x = 0

0 = 2 x^{2} + 5 x

x, f (x + 1) = - 2 x^{2} + x - 1

(6 - x)^{2} = - 9

What are the solutions to the equation 3(w+5)^2=27 ?
The solutions to the equation 3(w+5)^2=27 are w=-2,w=-8
Find the zeros of 3(w+5)^2=27
The zeros of 3(w+5)^2=27 are w=-2,w=-8