What are the solutions to the equation 0=-2x^2-16x-30 ?

The solutions to the equation 0=-2x^2-16x-30 are x=-5,x=-3

Find the zeros of 0=-2x^2-16x-30

The zeros of 0=-2x^2-16x-30 are x=-5,x=-3

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0 = - 2 x^{2} - 16 x - 30

x = - 5, x = - 3

Solution steps

0 = - 2 x^{2} - 16 x - 30

Switch sides

- 2 x^{2} - 16 x - 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 ( - 2 ) ( - 30 )}{2 ( - 2 )}

(- 16)^{2} - 4 (- 2) (- 30) = 4

x_{1, 2} = \frac{- ( - 16 ) \pm 4}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4}{2 ( - 2 )}, x_{2} = \frac{- ( - 16 ) - 4}{2 ( - 2 )}

x = \frac{- ( - 16 ) + 4}{2 ( - 2 )} : - 5

x = \frac{- ( - 16 ) - 4}{2 ( - 2 )} : - 3

The solutions to the quadratic equation are:

x = - 5, x = - 3

4 x^{2} + 30 x - 54 = 0

- 12 x + x^{2} = 28

(x - 2)^{2} = 50

2 x^{2} - 4 x + c = 0

4 x^{2} + 8 x = - 1

What are the solutions to the equation 0=-2x^2-16x-30 ?
The solutions to the equation 0=-2x^2-16x-30 are x=-5,x=-3
Find the zeros of 0=-2x^2-16x-30
The zeros of 0=-2x^2-16x-30 are x=-5,x=-3