What are the solutions to the equation -x^2+2x=-1 ?

The solutions to the equation -x^2+2x=-1 are x=1-sqrt(2),x=1+sqrt(2)

Find the zeros of -x^2+2x=-1

The zeros of -x^2+2x=-1 are x=1-sqrt(2),x=1+sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

- x^{2} + 2 x = - 1

x = 1 - 2, x = 1 + 2

Decimal Notation

x = - 0.41421 \dots, x = 2.41421 \dots

Solution steps

- x^{2} + 2 x = - 1

Move

1

to the left side

- x^{2} + 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) \cdot 1}{2 ( - 1 )}

2^{2} - 4 (- 1) \cdot 1 = 22

x_{1, 2} = \frac{- 2 \pm 2 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2 + 2 2}{2 ( - 1 )}, x_{2} = \frac{- 2 - 2 2}{2 ( - 1 )}

x = \frac{- 2 + 2 2}{2 ( - 1 )} : 1 - 2

x = \frac{- 2 - 2 2}{2 ( - 1 )} : 1 + 2

The solutions to the quadratic equation are:

x = 1 - 2, x = 1 + 2

2 y^{2} = 16

2 y^{2} = 54

x, x^{2} + 5 x = - y + 6 a

c^{2} - 15 c + 54 = 0

a = 5 x (3 x + 2)

What are the solutions to the equation -x^2+2x=-1 ?
The solutions to the equation -x^2+2x=-1 are x=1-sqrt(2),x=1+sqrt(2)
Find the zeros of -x^2+2x=-1
The zeros of -x^2+2x=-1 are x=1-sqrt(2),x=1+sqrt(2)