What are the solutions to the equation 0=5x^2+29x-6 ?

The solutions to the equation 0=5x^2+29x-6 are x= 1/5 ,x=-6

Find the zeros of 0=5x^2+29x-6

The zeros of 0=5x^2+29x-6 are x= 1/5 ,x=-6

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0 = 5 x^{2} + 29 x - 6

x = \frac{1}{5}, x = - 6

Decimal Notation

x = 0.2, x = - 6

Solution steps

0 = 5 x^{2} + 29 x - 6

Switch sides

5 x^{2} + 29 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 29 \pm 2 9 ^{2} - 4 \cdot 5 ( - 6 )}{2 \cdot 5}

2 9^{2} - 4 \cdot 5 (- 6) = 31

x_{1, 2} = \frac{- 29 \pm 31}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 29 + 31}{2 \cdot 5}, x_{2} = \frac{- 29 - 31}{2 \cdot 5}

x = \frac{- 29 + 31}{2 \cdot 5} : \frac{1}{5}

x = \frac{- 29 - 31}{2 \cdot 5} : - 6

The solutions to the quadratic equation are:

x = \frac{1}{5}, x = - 6

6 x^{2} - 49 = 0

x^{2} = - 17 x

x^{2} = - 175

x^{2} - 180 x + 20000 = 0

2 x^{2} - 16 x + 7

What are the solutions to the equation 0=5x^2+29x-6 ?
The solutions to the equation 0=5x^2+29x-6 are x= 1/5 ,x=-6
Find the zeros of 0=5x^2+29x-6
The zeros of 0=5x^2+29x-6 are x= 1/5 ,x=-6