What are the solutions to the equation factor x^2+2x-99=0 ?

The solutions to the equation factor x^2+2x-99=0 are x=9,x=-11

Find the zeros of factor x^2+2x-99=0

The zeros of factor x^2+2x-99=0 are x=9,x=-11

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x^{2} + 2 x - 99 = 0

x = 9, x = - 11

Solution steps

x^{2} + 2 x - 99 = 0

Factor

x^{2} + 2 x - 99 : (x - 9) (x + 11)

(x - 9) (x + 11) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 9 = 0 or x + 11 = 0

Solve

x - 9 = 0 : x = 9

Solve

x + 11 = 0 : x = - 11

The solutions to the quadratic equation are:

x = 9, x = - 11

t^{2} - 2 t + 8 = 0

- 31 = 2 - 3 a^{2}

x, 3 x^{2} - 2 x + 2 = 0

x, f^{- 1} (x) = x^{2} + 5

(x - 1) (2 x - 3) = 1

What are the solutions to the equation factor x^2+2x-99=0 ?
The solutions to the equation factor x^2+2x-99=0 are x=9,x=-11
Find the zeros of factor x^2+2x-99=0
The zeros of factor x^2+2x-99=0 are x=9,x=-11