What are the solutions to the equation 9v^2+2=-4v ?

The solutions to the equation 9v^2+2=-4v are v=-2/9+i(sqrt(14))/9 ,v=-2/9-i(sqrt(14))/9

Find the zeros of 9v^2+2=-4v

The zeros of 9v^2+2=-4v are v=-2/9+i(sqrt(14))/9 ,v=-2/9-i(sqrt(14))/9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9 v^{2} + 2 = - 4 v

v = - \frac{2}{9} + i \frac{14}{9}, v = - \frac{2}{9} - i \frac{14}{9}

Solution steps

9 v^{2} + 2 = - 4 v

Move

4 v

to the left side

9 v^{2} + 2 + 4 v = 0

Write in the standard form

a x^{2} + b x + c = 0

9 v^{2} + 4 v + 2 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 9 \cdot 2}{2 \cdot 9}

Simplify

4^{2} - 4 \cdot 9 \cdot 2 : 214 i

v_{1, 2} = \frac{- 4 \pm 2 14 i}{2 \cdot 9}

Separate the solutions

v_{1} = \frac{- 4 + 2 14 i}{2 \cdot 9}, v_{2} = \frac{- 4 - 2 14 i}{2 \cdot 9}

v = \frac{- 4 + 2 14 i}{2 \cdot 9} : - \frac{2}{9} + i \frac{14}{9}

v = \frac{- 4 - 2 14 i}{2 \cdot 9} : - \frac{2}{9} - i \frac{14}{9}

The solutions to the quadratic equation are:

v = - \frac{2}{9} + i \frac{14}{9}, v = - \frac{2}{9} - i \frac{14}{9}

3 x^{2} - 18 x + 30 = 0

3 x^{2} = \frac{1}{3}

24 + 10 x - x^{2}

3 y^{2} - 3 y - 2 = - 5 y

aa = 0, (a^{0})

What are the solutions to the equation 9v^2+2=-4v ?
The solutions to the equation 9v^2+2=-4v are v=-2/9+i(sqrt(14))/9 ,v=-2/9-i(sqrt(14))/9
Find the zeros of 9v^2+2=-4v
The zeros of 9v^2+2=-4v are v=-2/9+i(sqrt(14))/9 ,v=-2/9-i(sqrt(14))/9