What are the solutions to the equation 2y(y+5)-5=0 ?

The solutions to the equation 2y(y+5)-5=0 are y=(-5+sqrt(35))/2 ,y=-(5+sqrt(35))/2

Find the zeros of 2y(y+5)-5=0

The zeros of 2y(y+5)-5=0 are y=(-5+sqrt(35))/2 ,y=-(5+sqrt(35))/2

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2 y (y + 5) - 5 = 0

y = \frac{- 5 + 35}{2}, y = - \frac{5 + 35}{2}

Decimal Notation

y = 0.45803 \dots, y = - 5.45803 \dots

Solution steps

2 y (y + 5) - 5 = 0

Expand

2 y (y + 5) - 5 : 2 y^{2} + 10 y - 5

2 y^{2} + 10 y - 5 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

1 0^{2} - 4 \cdot 2 (- 5) = 235

y_{1, 2} = \frac{- 10 \pm 2 35}{2 \cdot 2}

Separate the solutions

y_{1} = \frac{- 10 + 2 35}{2 \cdot 2}, y_{2} = \frac{- 10 - 2 35}{2 \cdot 2}

y = \frac{- 10 + 2 35}{2 \cdot 2} : \frac{- 5 + 35}{2}

y = \frac{- 10 - 2 35}{2 \cdot 2} : - \frac{5 + 35}{2}

The solutions to the quadratic equation are:

y = \frac{- 5 + 35}{2}, y = - \frac{5 + 35}{2}

y^{2} + 18 y - 40 = 0

x^{2} + 6 x = 55

k (k - 1) = 12

y^{2} + 2 y - 48 = 0

(x + 4) (x - 6) = 5 (x - 6)

What are the solutions to the equation 2y(y+5)-5=0 ?
The solutions to the equation 2y(y+5)-5=0 are y=(-5+sqrt(35))/2 ,y=-(5+sqrt(35))/2
Find the zeros of 2y(y+5)-5=0
The zeros of 2y(y+5)-5=0 are y=(-5+sqrt(35))/2 ,y=-(5+sqrt(35))/2