What are the solutions to the equation 121x^2-8=0 ?

The solutions to the equation 121x^2-8=0 are x=(2sqrt(2))/(11),x=-(2sqrt(2))/(11)

Find the zeros of 121x^2-8=0

The zeros of 121x^2-8=0 are x=(2sqrt(2))/(11),x=-(2sqrt(2))/(11)

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121 x^{2} - 8 = 0

x = \frac{2 2}{11}, x = - \frac{2 2}{11}

Decimal Notation

x = 0.25712 \dots, x = - 0.25712 \dots

Solution steps

121 x^{2} - 8 = 0

Move

8

to the right side

121 x^{2} = 8

Divide both sides by

121

x^{2} = \frac{8}{121}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{8}{121}, x = - \frac{8}{121}

\frac{8}{121} = \frac{2 2}{11}

- \frac{8}{121} = - \frac{2 2}{11}

x = \frac{2 2}{11}, x = - \frac{2 2}{11}

- x^{2} + 4 x + 2

lo g_{3} (2) x^{2} = lo g_{3} (72)

2 x^{2} + 24 x - 60 = x (x + 13)

x, x^{2} - 6 x = y^{2} - 6 y

5 x^{2} + 4 = 1129

What are the solutions to the equation 121x^2-8=0 ?
The solutions to the equation 121x^2-8=0 are x=(2sqrt(2))/(11),x=-(2sqrt(2))/(11)
Find the zeros of 121x^2-8=0
The zeros of 121x^2-8=0 are x=(2sqrt(2))/(11),x=-(2sqrt(2))/(11)