What are the solutions to the equation (3x+4)^2=49 ?

The solutions to the equation (3x+4)^2=49 are x=1,x=-11/3

Find the zeros of (3x+4)^2=49

The zeros of (3x+4)^2=49 are x=1,x=-11/3

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(3 x + 4)^{2} = 49

x = 1, x = - \frac{11}{3}

Decimal Notation

x = 1, x = - 3.66666 \dots

Solution steps

(3 x + 4)^{2} = 49

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 4 = 49 : x = 1

Solve

3 x + 4 = - 49 : x = - \frac{11}{3}

The solutions to the quadratic equation are:

x = 1, x = - \frac{11}{3}

- y^{2} = 3 y - 7

18 x^{2} + 19 x - 7 = 0

3 x (x - 3) = 6 x^{2} - 11 x

x \cdot x = 5 x

x \cdot x = 36

What are the solutions to the equation (3x+4)^2=49 ?
The solutions to the equation (3x+4)^2=49 are x=1,x=-11/3
Find the zeros of (3x+4)^2=49
The zeros of (3x+4)^2=49 are x=1,x=-11/3