What are the solutions to the equation -2x+x^2=15 ?

The solutions to the equation -2x+x^2=15 are x=5,x=-3

Find the zeros of -2x+x^2=15

The zeros of -2x+x^2=15 are x=5,x=-3

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- 2 x + x^{2} = 15

x = 5, x = - 3

Solution steps

- 2 x + x^{2} = 15

Move

15

to the left side

- 2 x + x^{2} - 15 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 2 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 15 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 15) = 8

x_{1, 2} = \frac{- ( - 2 ) \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 8}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 8}{2 \cdot 1}

x = \frac{- ( - 2 ) + 8}{2 \cdot 1} : 5

x = \frac{- ( - 2 ) - 8}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 5, x = - 3

x, (x - 7)^{2} + (x - 7) - 6 = 0

(2 x + 1) (2 x + 3) = 195

3.4 a (a - 6) = 10 a + a - 6

8 x^{2} + x - 10 = 0

- 2 p^{2} + 7 p - 6 = 0

What are the solutions to the equation -2x+x^2=15 ?
The solutions to the equation -2x+x^2=15 are x=5,x=-3
Find the zeros of -2x+x^2=15
The zeros of -2x+x^2=15 are x=5,x=-3