What are the solutions to the equation 2x^2+12x-10=0 ?

The solutions to the equation 2x^2+12x-10=0 are x=-3+sqrt(14),x=-3-sqrt(14)

Find the zeros of 2x^2+12x-10=0

The zeros of 2x^2+12x-10=0 are x=-3+sqrt(14),x=-3-sqrt(14)

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2 x^{2} + 12 x - 10 = 0

x = - 3 + 14, x = - 3 - 14

Decimal Notation

x = 0.74165 \dots, x = - 6.74165 \dots

Solution steps

2 x^{2} + 12 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 2 ( - 10 )}{2 \cdot 2}

1 2^{2} - 4 \cdot 2 (- 10) = 414

x_{1, 2} = \frac{- 12 \pm 4 14}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 12 + 4 14}{2 \cdot 2}, x_{2} = \frac{- 12 - 4 14}{2 \cdot 2}

x = \frac{- 12 + 4 14}{2 \cdot 2} : - 3 + 14

x = \frac{- 12 - 4 14}{2 \cdot 2} : - 3 - 14

The solutions to the quadratic equation are:

x = - 3 + 14, x = - 3 - 14

x, g = p (x - q)^{2} + r - 3

x^{2} - 242 = 0

- 6 x^{2} + 36 x - 84 = 0

x, f (x + 2) = 4 x^{2} + 5

9 x^{2} + 9 x - 1 = 0

What are the solutions to the equation 2x^2+12x-10=0 ?
The solutions to the equation 2x^2+12x-10=0 are x=-3+sqrt(14),x=-3-sqrt(14)
Find the zeros of 2x^2+12x-10=0
The zeros of 2x^2+12x-10=0 are x=-3+sqrt(14),x=-3-sqrt(14)