What are the solutions to the equation x^2-90x+25=0 ?

The solutions to the equation x^2-90x+25=0 are x=5(9+4sqrt(5)),x=5(9-4sqrt(5))

Find the zeros of x^2-90x+25=0

The zeros of x^2-90x+25=0 are x=5(9+4sqrt(5)),x=5(9-4sqrt(5))

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x^{2} - 90 x + 25 = 0

x = 5 (9 + 45), x = 5 (9 - 45)

Decimal Notation

x = 89.72135 \dots, x = 0.27864 \dots

Solution steps

x^{2} - 90 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 90 ) \pm ( - 90 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

(- 90)^{2} - 4 \cdot 1 \cdot 25 = 405

x_{1, 2} = \frac{- ( - 90 ) \pm 40 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 90 ) + 40 5}{2 \cdot 1}, x_{2} = \frac{- ( - 90 ) - 40 5}{2 \cdot 1}

x = \frac{- ( - 90 ) + 40 5}{2 \cdot 1} : 5 (9 + 45)

x = \frac{- ( - 90 ) - 40 5}{2 \cdot 1} : 5 (9 - 45)

The solutions to the quadratic equation are:

x = 5 (9 + 45), x = 5 (9 - 45)

3 x^{2} - 4 = 2 x

y^{2} = 225

4 x (x - 3) = 6 - 2 x

C, X^{2} + Y^{2} = C^{2}

y^{2} = 11 y

What are the solutions to the equation x^2-90x+25=0 ?
The solutions to the equation x^2-90x+25=0 are x=5(9+4sqrt(5)),x=5(9-4sqrt(5))
Find the zeros of x^2-90x+25=0
The zeros of x^2-90x+25=0 are x=5(9+4sqrt(5)),x=5(9-4sqrt(5))