What are the solutions to the equation 3s^2+0.5s+2=0 ?

The solutions to the equation 3s^2+0.5s+2=0 are s=-1/12+i(sqrt(95))/(12),s=-1/12-i(sqrt(95))/(12)

Find the zeros of 3s^2+0.5s+2=0

The zeros of 3s^2+0.5s+2=0 are s=-1/12+i(sqrt(95))/(12),s=-1/12-i(sqrt(95))/(12)

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3 s^{2} + 0.5 s + 2 = 0

s = - \frac{1}{12} + i \frac{95}{12}, s = - \frac{1}{12} - i \frac{95}{12}

Solution steps

3 s^{2} + 0.5 s + 2 = 0

Multiply both sides by

10

30 s^{2} + 5 s + 20 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 30 \cdot 20}{2 \cdot 30}

Simplify

5^{2} - 4 \cdot 30 \cdot 20 : 595 i

s_{1, 2} = \frac{- 5 \pm 5 95 i}{2 \cdot 30}

Separate the solutions

s_{1} = \frac{- 5 + 5 95 i}{2 \cdot 30}, s_{2} = \frac{- 5 - 5 95 i}{2 \cdot 30}

s = \frac{- 5 + 5 95 i}{2 \cdot 30} : - \frac{1}{12} + i \frac{95}{12}

s = \frac{- 5 - 5 95 i}{2 \cdot 30} : - \frac{1}{12} - i \frac{95}{12}

The solutions to the quadratic equation are:

s = - \frac{1}{12} + i \frac{95}{12}, s = - \frac{1}{12} - i \frac{95}{12}

- x^{2} + 0 x + 1 = 0

3 x (2 x - 8) = 0

x^{2} - 19 x - 722 = 0

x^{2} + y^{2} = 1, x

(X - 5)^{2} = 9

What are the solutions to the equation 3s^2+0.5s+2=0 ?
The solutions to the equation 3s^2+0.5s+2=0 are s=-1/12+i(sqrt(95))/(12),s=-1/12-i(sqrt(95))/(12)
Find the zeros of 3s^2+0.5s+2=0
The zeros of 3s^2+0.5s+2=0 are s=-1/12+i(sqrt(95))/(12),s=-1/12-i(sqrt(95))/(12)