What are the solutions to the equation 96=96+80t-16t^2 ?

The solutions to the equation 96=96+80t-16t^2 are t=0,t=5

Find the zeros of 96=96+80t-16t^2

The zeros of 96=96+80t-16t^2 are t=0,t=5

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96 = 96 + 80 t - 16 t^{2}

t = 0, t = 5

Solution steps

96 = 96 + 80 t - 16 t^{2}

Switch sides

96 + 80 t - 16 t^{2} = 96

Move

96

to the left side

- 16 t^{2} + 80 t = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 80 \pm 8 0 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

8 0^{2} - 4 (- 16) \cdot 0 = 80

t_{1, 2} = \frac{- 80 \pm 80}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 80 + 80}{2 ( - 16 )}, t_{2} = \frac{- 80 - 80}{2 ( - 16 )}

t = \frac{- 80 + 80}{2 ( - 16 )} : 0

t = \frac{- 80 - 80}{2 ( - 16 )} : 5

The solutions to the quadratic equation are:

t = 0, t = 5

6 - x^{2} = 2

4 x^{2} + 20 = - 13

(8 - R)^{2} + (4 - R)^{2} = R^{2}

(x) = 4 x^{2} - 3

0.25 = x^{2}

What are the solutions to the equation 96=96+80t-16t^2 ?
The solutions to the equation 96=96+80t-16t^2 are t=0,t=5
Find the zeros of 96=96+80t-16t^2
The zeros of 96=96+80t-16t^2 are t=0,t=5