What are the solutions to the equation 32n^2-162=0 ?

The solutions to the equation 32n^2-162=0 are n= 9/4 ,n=-9/4

Find the zeros of 32n^2-162=0

The zeros of 32n^2-162=0 are n= 9/4 ,n=-9/4

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32 n^{2} - 162 = 0

n = \frac{9}{4}, n = - \frac{9}{4}

Decimal Notation

n = 2.25, n = - 2.25

Solution steps

32 n^{2} - 162 = 0

Move

162

to the right side

32 n^{2} = 162

Divide both sides by

32

n^{2} = \frac{81}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = \frac{81}{16}, n = - \frac{81}{16}

\frac{81}{16} = \frac{9}{4}

- \frac{81}{16} = - \frac{9}{4}

n = \frac{9}{4}, n = - \frac{9}{4}

x^{2} - 5 x + 4 = 0

- 18 x^{2} - 70 x + 8 = 0

2 x^{2} + 5 = 7 x

x \cdot (x - 1) = 0

x (x + 1) = - 1

What are the solutions to the equation 32n^2-162=0 ?
The solutions to the equation 32n^2-162=0 are n= 9/4 ,n=-9/4
Find the zeros of 32n^2-162=0
The zeros of 32n^2-162=0 are n= 9/4 ,n=-9/4