What are the solutions to the equation b^2-21=4 ?

The solutions to the equation b^2-21=4 are b=5,b=-5

Find the zeros of b^2-21=4

The zeros of b^2-21=4 are b=5,b=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

b^{2} - 21 = 4

b = 5, b = - 5

Solution steps

b^{2} - 21 = 4

Move

21

to the right side

b^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 25, b = - 25

25 = 5

- 25 = - 5

b = 5, b = - 5

7 = \frac{1}{2} (x + 6) 21 (x + 6)

3 c^{2} = 10 c - 8

8^{2} = 2 x^{2}

x^{2} + 18 x + 36 = 0

5 x^{2} - 20 x - 10 = 0

What are the solutions to the equation b^2-21=4 ?
The solutions to the equation b^2-21=4 are b=5,b=-5
Find the zeros of b^2-21=4
The zeros of b^2-21=4 are b=5,b=-5