What are the solutions to the equation 6p^2-5=2+5p^2-6p ?

The solutions to the equation 6p^2-5=2+5p^2-6p are p=-7,p=1

Find the zeros of 6p^2-5=2+5p^2-6p

The zeros of 6p^2-5=2+5p^2-6p are p=-7,p=1

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6 p^{2} - 5 = 2 + 5 p^{2} - 6 p

p = - 7, p = 1

Solution steps

6 p^{2} - 5 = 2 + 5 p^{2} - 6 p

Switch sides

2 + 5 p^{2} - 6 p = 6 p^{2} - 5

Move

5

to the left side

5 p^{2} - 6 p + 7 = 6 p^{2}

Move

6 p^{2}

to the left side

- p^{2} - 6 p + 7 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 1 ) \cdot 7}{2 ( - 1 )}

(- 6)^{2} - 4 (- 1) \cdot 7 = 8

p_{1, 2} = \frac{- ( - 6 ) \pm 8}{2 ( - 1 )}

Separate the solutions

p_{1} = \frac{- ( - 6 ) + 8}{2 ( - 1 )}, p_{2} = \frac{- ( - 6 ) - 8}{2 ( - 1 )}

p = \frac{- ( - 6 ) + 8}{2 ( - 1 )} : - 7

p = \frac{- ( - 6 ) - 8}{2 ( - 1 )} : 1

The solutions to the quadratic equation are:

p = - 7, p = 1

0 = 3 t^{2} - 12 t - 15

4 x^{2} + 180 = 0

2 x^{2} + 9 + 10 = 0

(x - 1) (2 x - 5) = 0

(22 - r)^{2} + (11 - r)^{2} = r^{2}

What are the solutions to the equation 6p^2-5=2+5p^2-6p ?
The solutions to the equation 6p^2-5=2+5p^2-6p are p=-7,p=1
Find the zeros of 6p^2-5=2+5p^2-6p
The zeros of 6p^2-5=2+5p^2-6p are p=-7,p=1